![]() For example, if your input is 2*3+1, you first calculate 2 × 3, which is okay, and then you calculate 3 + 1, which isn't okay: You want to calculate 6 + 1 here. COMPUTER OPERATIONS ( clerical ) chiel console operator senior console. That's bad.Īnother problem is that you always operate on two adjacent numbers, but that's not what you want. Automatic Data Processing - Equipment Operators This group includes occupations. The index 2*loop -1 will go out of bounds on the first number. It is clear that the index 2 * loop can go out of bounds. concalc 1+1 2 concalc sqrt2 1. concalc is also able to run scripts written in a C-like programming language. You can use it if you need a calculator in your shell. ![]() It is just the parser-algorithm of extcalc packed into a simple console program. You have two independent arrays, one for numbers, one for operators. Description: console calculator concalc is a calculator for the Linux console. In ASCII that's 43.Ĭalculation: There is also a problem with how you calculate your result. The notation '+' means the character code of the plus sign. Double quotations marks enclose strings, that is pointers to the first character of an array of characters. Strings versus characters: C distinguishes between single and double quotation marks. In that case, the next scanf starts before the unrecognized input, which will probably trip up your syntax. "Nothing read" means that there is input, but it can't be converted to a number, for example "four". You should also check the result, which would be 1 for "1 item read", 0 for "nothing read" ot EOF for "end of input", for example when the user hits Ctrl-D or Ctrl-Z. The operator &number_in creates such a pointer: scanf("%d", &number_in) // like above, but now on a correct number_in So scanf must store the scanned data by other means: You must pass a pointer to the data you want to scan. ![]() One way would be to return the scanned number, but scanf can read multiple inputs, so it chose to return a value that tells you whether the scanning was successful. When you read the input, the scanning function must be able to modify number_in. Your input is a whole number, an int, not a pointer to an int. Scanning the input: Your data input looks like this: int *number_in You can learn about some of them when you enable warnings. There are many problems with your program. ![]()
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